Problem : Write functions to:
🔰Reverse a list of elements.🔰Find the Sum of all elements in a list.🔰Check if a given elements exists in a list.
Solution:👇
Step 1: Define Functions:
👉The code defines three separate functions:
♦
reverse_list(my_list)
: This function takes a list (my_list
) as input and returns a new list with the elements in reverse order.
♦ sum_list(my_list)
: This function takes a list (my_list
) as input and returns the sum of all the elements in the list.
♦element_exists(my_list, element)
: This function takes two arguments: a list (my_list
) and an element (element
). It checks if the givenelement
exists within themy_list
and returnsTrue
if found,False
otherwise.
Steps 2: List Slicing (Reverse Function):
👉The
reverse_list
function utilizes Python's powerful list slicing syntax for efficient reversal. Here's how it works:
♦
my_list[::-1]
: This expression creates a slice of the original list (my_list
).
🔷The empty
:
in the middle indicates the entire list is being sliced.
🔷-1
specifies taking elements in reverse order (from the end to the beginning).
Step 3:
sum()
function (Sum Function):👉The
sum_list
function employs the built-insum()
function in Python. It takes an iterable (like a list) as input and returns the sum of all its elements.Sstep 4:
in
Operator (Element Exists Function):👉The
element_exists
function leverages thein
operator in Python. The expressionelement in my_list
evaluates toTrue
if theelement
is found within themy_list
, andFalse
if not.Step 5: Example Usage:
The code snippet demonstrates how to use these functions with an example list
my_list = [1, 2, 3, 4, 5]
:
print(reverse_list(my_list))
: Reverses the list and prints[5, 4, 3, 2, 1]
.print(sum_list(my_list))
: Calculates the sum and prints15
.print(element_exists(my_list, 3))
: Checks for element 3 and printsTrue
.
Good job keep it up
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